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A pair of bullocks exerts a force of $140\; N$ on a plough. The field being ploughed is $15\; m$ long. How much work is done in ploughing the length of the field?

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The work done is given by :

$W\ =\ F.s$

or $=\ 140\times 15\ =\ 2100\ Nm$

Hence the work done in ploughing the field is 2100 J.

Posted by

Sanket Gandhi

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