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  • A point charge +10 µC is a distance 5 cm directly above the centre of a square of side 10 cm, as shown in figure. What is the magnitude of the electric flux through the square? (Hint: Think of the square as one face of a cube with edge 10 cm.)

Q 1.18: A point charge +10 \mu C is a distance 5 cm directly above the center of a square of side 10 cm, as shown in Fig. What is the magnitude of the electric flux through the square? (Hint: Think of the square as one face of a cube with an edge of 10 cm.)

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Let us assume that the charge is at the center of the cube with an edge of 10 cm.

Using Gauss's law, we know that the flux of the electric field through any closed surface S is 1/\epsilon _{0}  times the total charge enclosed by S.

i.e.   \phi = q/\epsilon _{0}

where, q = net charge enclosed  and  \epsilon _{0} = permittivity of free space (constant)

Therefore, flux through the cube: \phi = (10\times10^{-6} C)/\epsilon _{0}

Due to symmetry, we can conclude that the flux through each side of the cube, \phi', will be equal.

\therefore \phi' = \frac{\phi}{6} = \frac{10^{-5}}{6\times\epsilon _{0}} = \frac{10^{-5}}{6\times\ 8.85\times10^{-12}} = \boldsymbol{1.9 \times 10^5\ Nm^2C^{-1}} 

Posted by

HARSH KANKARIA

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