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# A rod of length 1.05 m having negligible mass is supported at its ends by two wires of steel (wire A) and aluminium (wire B) of equal lengths as shown in Fig. 9.15. The cross-sectional areas of wires A and B are 1.0 mm2 and 2.0 mm2, respectively.

Q18 (b)  A rod of length 1.05 m having negligible mass is supported at its ends by two wires of steel (wire A) and aluminium (wire B) of equal lengths as shown in Fig. 9.15. The cross-sectional areas of wires A and B are
respectively. At what point along the rod should a mass m be suspended in order to produce equal strains in both steel and aluminium wires. Views

Cross-Sectional Area of wire A is AA = 1 mm2

Cross-Sectional Area of wire B is AB = 2 mm2

Let the Mass m be suspended at y distance From the wire A

Let the Tension in the two wires A and B be FA and FB respectively

Since the Strain in the wires is equal

Equating moments of the Tension in the wires about the point where mass m is suspended we have

The Load should be suspended at a point 43.2 cm from the wire A such that there is an equal strain in the two wires.

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