# 6. A solid iron pole consists of a cylinder of height 220 cm and base diameter 24 cm, which is surmounted by another cylinder of height 60 cm and radius 8 cm. Find the mass of the pole, given that 1 cm 3 of iron has approximately 8g mass. (Use $\pi = 3.14$)

The pole can be divided into one large cylinder and one small cylinder.

Thus, volume of pole  =  volume of large cylinder   +     volume of small cylinder

$=\ \pi r_l^2h_l\ +\ \pi r_s^2h_s$

or                                $=\ \pi \times 12^2\times 220\ +\ \pi \times 8^2\times 60$

or                                $=\ \pi \times \left ( 144\times 220\ +\ 64\times 60 \right )$

or                                $=\ 3.14\times 35520$

or                                $=\ 111532.5\ cm^3$

Now, according to question mass of the pole is :

$=\ 8\times 111532.5$

or                                                   $=\ 892262.4\ g\ =\ 892.262\ Kg$

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