Get Answers to all your Questions

header-bg qa

2.5     A solution of glucose in water is labelled as 10\%  w/w, what would be the molality and mole fraction of each component in the solution? If the density of solution is 1.2\; g\; mL^{-1},  then what shall be the molarity of the solution?

Answers (1)

best_answer

According to question, 10\% mass percentage means in 100 g of solution 10 g glucose is dissolved in 90 g water.

Molar mass of glucose (C6H12O6)  =  180\ g\ mol^{-1}

So moles of glucose are :

                                               \frac{10}{180} = 0.056 mol              

                               Moles\: of\: water = \frac{90}{18} = 5 mol             

                                       Molality = \frac{0.056}{0.09} = 0.62\ m

Mole fraction :-         

                                         \frac{0.056}{0.056+5} = 0.011

Molarity :-             Volume of 100 g solution  : 

                                                                                    =\frac{100}{1.2} =83.3\ mL

                                       Molarity = \frac{0.056}{83.33\times10^{-3}} =0.67\ M

                                           

                                    

Posted by

Devendra Khairwa

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads