Q 5.     A stone is thrown in a vertically upward direction with a velocity of 5\ m s^{-1}. If the acceleration of the stone during its motion is 10\ m s^{-2} in the downward direction, what will be the height attained by the stone and how much time will it take to reach there?

Answers (1)

Taking upward direction as positive (+) direction:

Given,

u = 5\ ms^{-1}

a = -10\ ms^{-2}         (This is due to gravitational force!)

The stone will move up until its velocity becomes zero.

\therefore v = 0\ ms^{-1}

We know, v^2 = u^2 + 2as

\\ \implies 0^2 = 5^2 + 2(-10)s \\ \implies 20 s = 25 \\ \implies s = 1.25\ m

Therefore, the stone reaches to a height of 1.25\ m

Now, 

We know, v = u + at

\\ \implies 0 = 5 + (-10)t \\ \implies t = 0.5\ s

Therefore, the time taken by the stone to reach the maximum height is 0.5\ s.

 

 

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