Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • NCERT
  • A string of mass 2.5 kg is under a tension of 200 N. The length of the stretched string is 20.0 m. If the transverse jerk is struck at one end of the string, the disturbance will reach the other end in (a) one second

A string of mass 2.5 kg is under a tension of 200 N. The length of the stretched string is 20.0 m. If the transverse jerk is struck at one end of the string, the disturbance will reach the other end in
(a) one second
(b) 0.5 second
(c) 2 seconds
(d) data given is insufficient

Answers (1)

The answer is the option (b) M= mass of string= 2.5Kg, l=20m

μ=mass per unit length= \frac{M}{l}=\frac{2.5}{20} = 0.125 kg/m

v=\sqrt{ \frac{T}{\mu }}=\sqrt{\frac{200}{0.125}}=\sqrt{1600}=\frac{40m}{s}

Time =

\frac{distance }{speed}= \frac{20m}{\frac{40m}{s}}=\frac{1}{2}sec=0.5 sec

Posted by

infoexpert24

View full answer

Similar Questions

Latest Question