A train starting from a railway station and moving with uniform acceleration attains a speed 40 km h-1 in 10 minutes. Find its acceleration.

Answers (1)

(We know, 1\ km = 1000\ m ; 1\ hr = 3600\ s)

Given, The train starts from rest. Hence, the initial speed of the train = 0\ kmh^{-1} = 0\ ms^{-1}

Final speed of the train = 40\ kmh^{-1} = \frac{40\times1000}{3600} = \frac{100}{9} ms^{-1}

Time taken, t = 10\ min = 10\times60\ s = 600\ s

We know, v = u+at

\\ \implies \frac{100}{9} = 0+a(600) \\ \implies a = \frac{100}{9\times600} = \frac{1}{6\times9} \\ \implies a = \frac{1}{54} = 0.0185\ ms^{-2}

Therefore, the acceleration of the train is  0.0185\ ms^{-2}

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