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# A vertical pole of length 6 m casts a shadow 4 m long on the ground and at the same time a tower casts a shadow 28 m long. Find the height of the tower.

Q15  A vertical pole of length 6 m casts a shadow 4 m long on the ground and at the same time
a tower casts a shadow 28 m long. Find the height of the tower.

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CD = pole

AB = tower

In $\triangle ABE\, \, and\, \triangle CDF,$

$\angle CDF=\angle ABE$            ( Each $90 \degree$)

$\angle DCF=\angle BAE$             (Angle of sun at same place )

$\triangle ABE\, \, \sim \, \triangle CDF,$          (AA similarity)

$\frac{AB}{CD}=\frac{BE}{QL}$

$\Rightarrow \frac{AB}{6}=\frac{28}{4}$

$\Rightarrow AB=42$  cm

Hence, the height of the tower is 42 cm.

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