# A1 kW signal is transmitted using a communication channel which provides attenuation at the rate of -2dB per km. If the communication channel has a total length of 5 km, the power of the signal received is [gain in dB =10 log(p0/pi)](a) 900 W    (b) 100 W    (c) 990 W    (d) 1010 W

To calculate the power of the signal transmitted,

The rate of attenuation of the signal $= -2(dB/km)$

The given total length of the path$= 5 km$

The formula used $\Rightarrow dB = 10\log(P_o/P_i)$

After putting all he values,

$P_o = 100W$

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