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  • An adult weighing 600 N raises the centre of gravity of his body by 0.25 m while taking each step of 1 m length in jogging.

An adult weighing 600 N raises the centre of gravity of his body by 0.25 m while taking each step of 1 m length in jogging. If he jogs for 6 km, calculate the energy utilized by him in jogging assuming that there is no energy loss due to friction of ground and air. Assuming that the body of the adult is capable of converting 10% of energy intake in the form of food, calculate the energy equivalents of food that would be required to compensate energy utilized for jogging.

Answers (1)

Potential energy required by the jogger to raise each step = mgh

mg = 600N, h = 0.25 m

Number of steps travelled in 6 km = 6000

Total Energy for 6000 steps = 6000 \times 600 \times 0.25

Jogging utilises 10% of the total energy = \frac{10}{100}\times 6000 \times 600 \times 0.25

= 90,000 J

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