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An amplitude modulated wave is as shown in the figure. Calculate

(i) the percentage modulation

(ii) peak carrier voltage and

(iii) peak value of information voltage

Answers (1)

Explanation:-

As shown in the figure,

Maximum voltage, Vmax = 100/2 = 50 V

Minimum voltage, Vmin = 20/2 = 10 V

i) The percentage modulation quantifies how much the amplitude of the carrier wave is varied by the modulating signal.

Percentage modulation = (Vmax - Vmin)/(Vmax + Vmin) \times 100

After substituting the values of Vmax and Vmin, the percentage modulation = 66.67%

ii) the formula of peak carrier voltage is Vc =( Vmax + Vmin)/2

Thus,Vc = 30 V

iii) Peak value of information voltage  = Vm = uVc = 20V

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