Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • NCERT
  • An element with molar mass 2.7x10 to the power of -2 kg mol to the power of -1 forms a cubic unit cell with edge length 450 pm.

1.18.   An element with molar mass  2.7\times 10^{-2}kg\; mol^{-1}  forms a cubic unit cell with edge length 405\; pm. If its density is 2.7\times 103\; kg\; m^{-3}, what is the nature of the cubic unit cell?

Answers (1)

best_answer

We know that :

                           Density\ of\ unit\ cell = \frac{z.M}{a^3.N_A}

We are given :        Density = 2.7\times10^3\ Kg\ m^{-3}

and                        Molar\ mass = 2.7\times10^{-2}\ Kg\ mol^{-1}

and                      Edge\ length = 405 pm =4.05\times10^{-10}\ m

  So we need to find z (no. of atoms present in unit cell) by putting all values in formula of density.

 We get,                          z \approx 4.

It is known that face centred cubic also has 4 atoms in its unit cell, So given cubic unit cell is face centred.

Posted by

Devendra Khairwa

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

PM Modi's Pariksha Pe Charcha 2025 to be held next month, registrations open till January 14
anam-khan

CBSE Board Exams 2025: Online portal for availing exemptions by CWSN students opens
anam-khan

Board Exams: States agree to equivalence; no question paper ‘jumbling’ from next year, says PARAKH CEO

Latest Question