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An ion with mass number 37 possesses one unit of negative charge. If the ion contains 11.1% more neutrons than the electrons, find the symbol of the ion.

2.43    An ion with mass number 37 possesses one unit of negative charge. If the ion contains 11.1% more neutrons than the electrons, find the symbol of the ion.

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Given an ion has mass number 37 and possesses one unit of negative charge.

Let the number of electrons be 'e' then,

the number of neutrons will be: e+\frac{11.1e}{100} = 1.111e

The number of electrons in the neutral atom = e-1 (ion possesses one unit of negative charge).

Therefore, the number of protons will be = e-1.

Mass number = number of protons + number of neutrons

therefore, 

1.111e +e -1 =37

\Rightarrow 2.111e =38

\Rightarrow e =18

Therefore, the number of protons is equal to the atomic number.

\Rightarrow e-1 = 18-1 =17

Hence, the symbol for an ion will be:

_{17}^{37}\textrm{Cl}^{-1}

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