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# An ion with mass number 37 possesses one unit of negative charge. If the ion contains 11.1% more neutrons than the electrons, find the symbol of the ion.

2.43    An ion with mass number 37 possesses one unit of negative charge. If the ion contains 11.1% more neutrons than the electrons, find the symbol of the ion.

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Given an ion has mass number 37 and possesses one unit of negative charge.

Let the number of electrons be $'e'$ then,

the number of neutrons will be: $e+\frac{11.1e}{100} = 1.111e$

The number of electrons in the neutral atom $= e-1$ (ion possesses one unit of negative charge).

Therefore, the number of protons will be $= e-1$.

Mass number = number of protons + number of neutrons

therefore,

$1.111e +e -1 =37$

$\Rightarrow 2.111e =38$

$\Rightarrow e =18$

Therefore, the number of protons is equal to the atomic number.

$\Rightarrow e-1 = 18-1 =17$

Hence, the symbol for an ion will be:

$_{17}^{37}\textrm{Cl}^{-1}$

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