Q. 5   An urn contains 25 balls of which 10 balls bear a mark 'X' and the remaining 15 bear a mark 'Y'. A ball is drawn at random from the urn, its mark is noted down and it is replaced. If 6 balls are drawn in this way, find the probability that 

            (iv) the number of balls with 'X' mark and 'Y' mark will be equal.

Answers (1)
S seema garhwal

P(equal\, to\, the \, number\, of\, balls \, with \, X \, mark \, and\, Y \, mark )=P(Z=3)


                                    P(Z=3)=\frac{20\times 8\times 27}{15625}