Q

# At 300 K,36 g of glucose present in a litre of its solution has an osmotic pressure of 4.98 bar. If the osmotic pressure of the solution is 1.52 bars at the same temperature, what would be its concentration?

2.22    At $\inline 300 \; K,$ 36 g of glucose present in a litre of its solution has an osmotic pressure of $\inline 4.98\; bar.$ If the osmotic pressure of the solution is $\inline 1.52\; bars$ at the same temperature, what would be its concentration?

Views

According to given conditions we have same solution under same temperature. So we can write :

$\frac{\Pi _1}{C_1} = \frac{\Pi _2}{C_2}$                                                   $\left ( \Pi = C.R.T\ ; RT = \frac{\Pi }{C} \right )$

So, if we put all the given values in above equation, we get

$\frac{4.98}{\frac{36}{180}} = \frac{1.52}{C_2}$

or                                              $C_2 = \frac{1.52\times36}{4.98\times180} = 0.061 M$

Hence the required concentration is 0.061 M.

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