8.18   Balance the following redox reactions by ion – electron method 

(b) MnO_{4}^{-}(aq)+SO_{2}(g) \rightarrow Mn^{2+}(aq)+HSO_{4}^{-}

(In Acidic medium)

Answers (1)

Answer-

oxidation half reaction

SO_{2}+2H_{2}O\rightarrow HSO_{4}^{-}+3H^{+}+2e^{-}

reduction half reaction

MnO_{4}^{-}+8H^{+}+5e^{-}\rightarrow Mn^{2+}+4H_{2}O

Balancing the reaction

multiply the oxidation half by 5 and reduction half by 2 and then add these two reactions 

2MnO_{4}^{-}+5SO_{2}+2H_{2}O+H^{+}\rightarrow 2Mn^{2+}+5HSO_{4}^{-}

 

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