# 4.(ii)    By giving a counter example, show that the following statement is not true.   (ii) q: The equation $x^2 - 1 = 0$ does not have a root lying between 0 and 2.

Given,

The equation $x^2 - 1 = 0$ does not have a root lying between 0 and 2.

Let x = 1

$\therefore (1)^2 - 1 = 1 -1 =0$

Hence 1 is a root of the equation $x^2 - 1 = 0$.

But 1 lies between 0 and 2.

Hence the given statement is not true.

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