2.4   Calculate the mass of urea  (NH_{2}CONH_{2})  required in making  2.5 \; kg  of  0.25\; molal  aqueous solution.

Answers (1)

Let us assume that the mass of urea required be x g.

So moles of urea will be :

                                                 Moles = \frac{Given\ mass}{Molar\ mass} = \frac{x}{60}\ moles

                                                 Molality = \frac{Moles}{Mass\ of\ solvent\ in\ Kg} = \frac{\frac{x}{60}}{2.5-0.001x} = 0.25

                                                 we get      x =  37

Thus mass of urea required = 37 g.

Related Chapters

Preparation Products

JEE Main Rank Booster 2021

This course will help student to be better prepared and study in the right direction for JEE Main..

₹ 13999/- ₹ 9999/-
Buy Now
Rank Booster NEET 2021

This course will help student to be better prepared and study in the right direction for NEET..

₹ 13999/- ₹ 9999/-
Buy Now
Knockout JEE Main April 2021 (Easy Installments)

An exhaustive E-learning program for the complete preparation of JEE Main..

₹ 4999/-
Buy Now
Knockout NEET May 2021

An exhaustive E-learning program for the complete preparation of NEET..

₹ 22999/- ₹ 14999/-
Buy Now
Knockout NEET May 2022

An exhaustive E-learning program for the complete preparation of NEET..

₹ 34999/- ₹ 24999/-
Buy Now
Exams
Articles
Questions