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Calculate the mass percentage of benzene C_6 H_6 and carbon tetrachloride CCl_4 if 22 g of benzene is dissolved in 122 g of carbon tetrachloride.

2.1   Calculate the mass percentage of benzene (C_{6}H_{6})  and carbon tetrachloride (CCl_{4})  if 22\; g of benzene is dissolved in 122\; g of carbon tetrachloride.

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We know that solute and solvent forms solution.

So mass percentage of benzene (solute)   :-  

                                                                       =\frac{22}{22+122}\times100 = \frac{22}{144}\times100 = 15.28\%

Similarly mass percentage of CCl4 :- 

                                                                           =\frac{122}{22+122}\times100 = \frac{122}{144}\times100 = 84.72\%

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