2.1   Calculate the mass percentage of benzene (C_{6}H_{6})  and carbon tetrachloride (CCl_{4})  if 22\; g of benzene is dissolved in 122\; g of carbon tetrachloride.

Answers (1)

We know that solute and solvent forms solution.

So mass percentage of benzene (solute)   :-  

                                                                       =\frac{22}{22+122}\times100 = \frac{22}{144}\times100 = 15.28\%

Similarly mass percentage of CCl4 :- 

                                                                           =\frac{122}{22+122}\times100 = \frac{122}{144}\times100 = 84.72\%

Related Chapters

Preparation Products

Knockout JEE Main April 2021

An exhaustive E-learning program for the complete preparation of JEE Main..

₹ 22999/- ₹ 14999/-
Buy Now
Knockout NEET May 2021

An exhaustive E-learning program for the complete preparation of NEET..

₹ 22999/- ₹ 14999/-
Buy Now
Knockout JEE Main April 2022

An exhaustive E-learning program for the complete preparation of JEE Main..

₹ 34999/- ₹ 24999/-
Buy Now
Test Series NEET May 2021

Take chapter-wise, subject-wise and Complete syllabus mock tests and get in depth analysis of your test..

₹ 6999/- ₹ 4999/-
Buy Now
Rank Booster NEET 2021

This course will help student to be better prepared and study in the right direction for NEET..

₹ 13999/- ₹ 9999/-
Buy Now
Boost your Preparation for JEE Main with our Foundation Course
 
Exams
Articles
Questions