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# Calculate the mole fraction of benzene in solution containing 30% by mass in carbon tetrachloride.

2.2   Calculate the mole fraction of benzene in solution containing $30\%$ by mass in carbon tetrachloride.

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For calculating mole fraction, we need moles of both the compounds.

It is given that benzene is $30\%$ in the solution by mass.

So if we consider 100g of solution then 30g is benzene and 70g is CCl4.

$Moles of CCl_{4}= \frac{Given\ mass}{Molar\ mass} = \frac{70}{154} = 0.4545\ mol$

$\left ( Molar\ mass\ of\ CCl_4 = 12 + 4(35.5) \right )$

Similarly moles of benzene :

$= \frac{30}{78} = 0.3846$                                                                                    $\left ( Molar\ mass\ of\ benzene = 6(12) + 6(1) \right )$

So mole fraction of benzene is given  :

$= \frac{0.3846}{0.3846+0.4545}$

$= 0.458$

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