Certain force acting on a 20 kg mass changes its velocity from 5 m s power of minus 1 to 2 m s power of minus 1 Calculate the work done by the force

Answers (1)

Mass.m = 20 kg.

Initial velocity, u=5m/s

Final velocity, v=2m/s

Work done = change in K.E.

W = \frac{1}{2}m u^2 -\frac{1}{2}m v^2 = \frac{1}{2}m( u^2- v^2)

      = \frac{1}{2}20( 2^2- 5^2) = -210J 

     

 

the negative sign implies the retarding 

nature of the applied force.

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