Q5 Check whether can end with the digit 0 for any natural number n.
By prime factorizing we have
6n = 2n x 3n
A number will end with 0 if it has at least 1 as the power of both 2 and 5 in its prime factorization. Since the power of 5 is 0 in the prime factorization of 6n we can conclude that for no value of n 6n will end with the digit 0.
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