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# Chlorine is prepared in the laboratory by treating manganese dioxide (MnO 2 ) with aqueous hydrochloric acid according to the reaction 4 HCl (aq) + MnO 2 (s) gives 2H 2 O (l) + MnCl 2 (aq) + Cl 2 (g) How many grams of HCl react with 5.0 g of

1.36    Chlorine is prepared in the laboratory by treating manganese dioxide (MnO2) with aqueous hydrochloric acid according to the reaction

$4 HCl (aq) + MnO_2 (s) \rightarrow 2H_2 O (l) + MnCl_2 (aq) + Cl_2 (g)$

How many grams of HCl react with 5.0 g of manganese dioxide?

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Molar mass of $MnO_{2}$ is $55+32 g = 87g$.

Here from the reaction 1 mole of $MnO_{2}$ reacts with 4 moles of $HCl$,

i.e., $4\times36.5g =146g$ of $HCl$.

Therefore, $5.0 g$ of $MnO_{2}$ will react with $HCl$:

$= \frac{146}{87}\times5.0g = 8.40g.$

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