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  • Consider a uniform electric field E = 3 × 10^3 î N/C. What is the flux of this field through a square of 10 cm on a side whose plane is parallel to the yz plane?

Q 1.15(a): Consider a uniform electric field E=3\times 10^{3}\ \widehat{i}\ N/C. (a) What is the flux of this field through a square of 10 cm on a side whose plane is parallel to the yz plane?

Answers (1)

best_answer

Given, 

E=3\times 10^{3}\ \widehat{i}\ \frac{N}{C}

Area of the square = 0.01^2\ m^2

Since the square is parallel to the yz plane, Therefore it's normal is in x-direction.(i.e \widehat{i} direction )

Therefore, flux through this surface:

\phi = E.A

\implies \phi = (3\times10^3\ \widehat{i}).(0.01\ \widehat{i}) Nm^2/C = \boldsymbol{30 Nm^2/C} 

Posted by

HARSH KANKARIA

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