Q

# Consider the reaction:

3.12    Consider the reaction:  $Cr_{2}O_{7}^{2-}+ 14H^+ + 6e^-\rightarrow 2cr^{3+} + 7H_{2}O$
What is the quantity of electricity in coulombs needed to reduce 1 mol  of $Cr_{2}O_{7}^{2-}$ ?

Views

It is clear from the given reaction that reduction of 1 mol of Cr2O72- will be

=   6 F                                                            (as 6 electrons are required to balance the reaction;  Charge required = nF)

$= 6\times96500$

$= 579000\ C$

Thus 578922 C charge is required for reduction of 1 mol of Cr2O72- .

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