# 2.   Construct a triangle of sides 4 cm, 5 cm and 6 cm and then a triangle similar to it whose sides are 2/3  of the corresponding sides of the first triangle.

D Devendra Khairwa

Steps of construction are:-

(i) Firstly draw a line segment AB of length 4 cm.

(ii) Now cut an arc of radius 5 cm from point A and an arc of 6 cm from point B.

(iii) Name the point of intersection of arcs to be point C.

(iv) Now join point AC and BC. Thus $\Delta$ ABC is the required triangle.

(v) Draw a line AD which makes an acute angle with AB and is opposite of vertex C.

(vi) Cut three equal parts of line AD namely  AA1, AA2, AA3.

(vii) Now join A3 to B. Draw a line A2B' parallel to A3B.

(viii) And then draw a line B'C' parallel to BC.

Hence $\Delta$ AB'C' is the required triangle.

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