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Describe the change in hybridisation (if any) of the Al atom in the following reaction.

4.25     Describe the change in hybridisation (if any) of the Al  atom in the following reaction.

                 AlCl_{3}+Cl^{-}\rightarrow AlCl_{4}^{-}

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Initially, the aluminium is in the ground state and the valence orbital can be shown as:

Then the electron gets excited so, the valence orbital can be shown as:

excited state

So, initially, aluminium (AlC_{3}) was sp^2 hybridisation and hence having a trigonal planar shape.

Then it reacts with chloride ion to form AlC_{4}^{-}. Where it has the empty 3p_{z} orbital which gets involved and the hybridisation changes from sp^2 \rightarrow sp^3.

Hence there is a shape change from trigonal planar to tetrahedral.

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