During an experiment, a signal from a spaceship reached the ground station in five minutes. What was the distance of the spaceship from the ground station? The signal travels at the speed of light, that is, 3 \times 10^{8}ms^{-1}.

Answers (1)

Given, the signal travels at the speed of light,  v = 3 \times 10^{8}ms^{-1}.

Time taken by the signal =5\ mins = 5\times60 s= 300\ s

Let the distance of the spaceship from the ground station be D\ m

We know, Speed = \frac{Distance\ travelled }{Time\ taken}

\\ \implies v = \frac{D}{t} \\ \\ \implies D = v\times t = 3\times10^8 \times 300

\\ \implies D = 9\times10^{10}\ m

Therefore, the distance of spaceship from the ground station is 9\times10^{10}\ m

 

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