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# E is a point on the side AD produced of a parallelogram ABCD and BE intersects CD at F. Show that triangle ABE similar to Delta CFB.

Q8 E is a point on the side AD produced of a parallelogram ABCD and BE intersects CD
at F. Show that $\Delta ABE \sim \Delta CFB$

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To prove : $\Delta ABE \sim \Delta CFB$

In $\Delta ABE \, \, \, and\, \, \Delta CFB$,

$\angle A=\angle C$   ( Opposite angles of a parallelogram are equal)

$\angle AEB=\angle CBF$  ( Alternate angles of AE||BC)

$\Delta ABE \sim \Delta CFB$     ( By AA criterion )

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