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E is a point on the side AD produced of a parallelogram ABCD and BE intersects CD at F. Show that triangle ABE similar to Delta CFB.

Q8 E is a point on the side AD produced of a parallelogram ABCD and BE intersects CD
          at F. Show that \Delta ABE \sim \Delta CFB

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To prove : \Delta ABE \sim \Delta CFB

In \Delta ABE \, \, \, and\, \, \Delta CFB,

  \angle A=\angle C   ( Opposite angles of a parallelogram are equal)

\angle AEB=\angle CBF  ( Alternate angles of AE||BC)

\Delta ABE \sim \Delta CFB     ( By AA criterion ) 

 

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