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  • Evaluate the following limits limit x tends to 0 cos x by pi minus x

16.  Evaluate the following limits \lim_{x\rightarrow 0}\frac{\cos x }{\pi -x }

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The limit

\lim_{x\rightarrow 0}\frac{\cos x }{\pi -x }

the function behaves well on directly putting the limit,so we put the limit directly. So.

\lim_{x\rightarrow 0}\frac{\cos x }{\pi -x }

=\frac{\cos (0) }{\pi -(0) }

=\frac{1 }{\pi }   (Answer)

Posted by

Pankaj Sanodiya

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