7.  Express sin 67^{o}+\cos 75^{o}in terms of trigonometric ratios of angles between 0^{o} and 45^{o}.

Answers (1)
M manish

By using the identity of \sin\theta and \cos\theta
sin 67^{o}+\cos 75^{o}
We know that, 
\sin(90-\theta) =\cos \theta and \cos(90-\theta) =\sin \theta
the above equation can be written as;
=\sin (90^0-23^0)+\cos(90^0-15^0)
=\sin (15^0)+\cos(23^0)

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