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Q 6.     Figure shows the distance-time graph of three objects A, B and C. Study the graph and answer the following questions:

            

  (c)     How far has C travelled when B passes A?

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In the given distance-time graph. Any point on the curve will give the distance of the object from O. To find how far C has travelled when B passes A, draw a perpendicular from the intersection point of A and B on the time axis. The point where it intersects on the C graph, from C, draws a perpendicular to the y-axis. Therefore, the distance travelled by C will be (Final distance from O - Initial distance from O)

On the distance axis :

7 small boxes = 4 km

Therefore 1 small box = \frac{4}{7}\frac{4}{7}km

Initially, object C is 4 blocks away from the origin.

Therefore, the initial distance of object C from the origin

\frac{4\times4}{7}=\frac{16}{7}

Distance of object C from the origin when B passes A = \frac{4}{7}\times16=\frac{64}{7}

Distance covered by C = \frac{64}{7}-\frac{16}{7}=\frac{48}{7}=6.85km

Hence, the total distance covered by C when B passes A is 6.85 km

Posted by

HARSH KANKARIA

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