Find: \frac{-13}{7}+\frac{6}{7},\frac{19}{5}+\left ( \frac{-7}{5} \right )

Answers (1)

For the given sum:  \frac{-13}{7}+\frac{6}{7}

Here the denominator value is same that is 7 hence we can sum the numerator as:

\frac{-13}{7}+\frac{6}{7}= \frac{-13+6}{7} = \frac{-7}{7} = -1

For the given sum:  \frac{19}{5}+\left ( \frac{-7}{5} \right )

Here also the denominator value is the same and is equal to 5 hence we can write it as:

\frac{19}{5}+\left ( \frac{-7}{5} \right ) = \frac{19-7}{5} = \frac{12}{5}

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