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  • Find a vector in the direction of vector which has magnitude 8 units.

Q.10  Find a vector in the direction of vector5 \hat i - \hat j + 2 \hat k which has magnitude 8 units.

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Given a vector 

\vec a=5 \hat i - \hat j + 2 \hat k

the unit vector in the direction of  5 \hat i - \hat j + 2 \hat k

\vec u=\frac{5\hat i - \hat j + 2 \hat k}{\sqrt{5^2+(-1)^2+2^2}}=\frac{5\hat i}{\sqrt{30}}-\frac{\hat j}{\sqrt{30}}+\frac{2\hat k}{\sqrt{30}}

A vector in direction of 5 \hat i - \hat j + 2 \hat k and whose magnitude is 8 =

8\vec u=\frac{40\hat i}{\sqrt{30}}-\frac{8\hat j}{\sqrt{30}}+\frac{16\hat k}{\sqrt{30}}

 

Posted by

Pankaj Sanodiya

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