# Q : 7      Find equation of the line parallel to the line  $3x-4y+2=0$  and passing through  the point $(-2,3)$.

G Gautam harsolia

It is given that line is parallel to line  $3x-4y+2=0$ which implies that the slopes of both the lines are equal
we can rewrite it as
$y = \frac{3x}{4}+\frac{1}{2}$
The slope of line $3x-4y+2=0$  =  $\frac{3}{4}$
Now, the equation of the line passing through the point $(-2,3)$ and with slope $\frac{3}{4}$ is
$(y-3)=\frac{3}{4}(x-(-2))$
$4(y-3)=3(x+2)$
$4y-12=3x+6$
$3x-4y+18= 0$
Therefore, the equation of the line is  $3x-4y+18= 0$

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