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Find the centre and radius of the circles. 2 x ^2 + 2y ^ 2 - x = 0

9. Find the centre and radius of the circles.

       2x^2 + 2y^2 - x = 0

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As we know, 

The equation of the circle with centre ( h, k) and radius r is given by ;

(x-h)^2+(y-k)^2=r^2

Given here 

2x^2 + 2y^2 - x = 0

Can also be written in the form 

\left ( x-\frac{1}{4}\right )^2 + \left ( y-0 \right )^2 = \left ( \frac{1}{4} \right )^2

So, from comparing, we can see that 

r=\frac{1}{4}

Hence Center of the circle is the \left ( \frac{1}{4},0\right )Radius of the circle is   \frac{1}{4}.

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