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3.  Find the coordinates of the focus, axis of the parabola, the equation of the directrix and the length of the latus rectum.

     y^2 = -8x

Answers (1)

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Given, a parabola with equation 

y^2 =-8x

This is parabola of the form y^2=-4ax which opens towards left.

So,

By comparing the given parabola equation with the standard equation, we get,

-4a=-8

a=2

Hence,

Coordinates of the focus :

(-a,0)=(-2,0)

Axis of the parabola:

It can be seen that the axis of this parabola is X-Axis.

The equation of the directrix

x=a,\Rightarrow x=2\Rightarrow x-2=0

The length of the latus rectum:

4a=4(2)=8.

Posted by

Pankaj Sanodiya

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