Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • NCERT
  • Find the equation of the right bisector of the line segment joining the points (3, 4) and (–1, 2).

Q : 13     Find the equation of the right bisector of the line segment joining the points  (3,4) and   (-1,2). 

Answers (1)

best_answer

Right bisector means perpendicular line which divides the line segment into two equal parts
Now, lines are perpendicular which means their slopes are negative times inverse of each other
Slope of line passing through points   (3,4) and   (-1,2)  is
m'= \frac{4-2}{3+1}= \frac{2}{4}=\frac{1}{2}
Therefore, Slope of bisector line is
m = - \frac{1}{m'}= -2
Now, let (h , k) be the point of intersection of two lines 
It is given that point (h,k) divides the line segment joining point  (3,4) and   (-1,2) into two equal part which means it is the mid point 
Therefore,
h = \frac{3-1}{2} = 1\ \ \ and \ \ \ k = \frac{4+2}{2} = 3
(h,k) = (1,3)
Now, equation  of line passing through point (1,3) and with slope -2 is 
(y-3)=-2(x-1)\\ y-3=-2x+2\\ 2x+y=5
Therefore, equation of line is  2x+y=5

Posted by

Gautam harsolia

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

CBSE Class 12 board exams 2025 to have 50% competency-based questions; no change in 10th
anam-khan

CBSE Class 12 board exams 2024 over; expected result date, trends of last 10 years
anam-khan

CBSE Class 12 accountancy board exam analysis 2024 out; paper rated easy, balanced

Latest Question