Get Answers to all your Questions

header-bg qa

Q1.    Find the nature of the roots of the following quadratic equations. If the real roots exist, find them:

                (i)    2x^2 - 3x +5 = 0

Answers (1)


For a quadratic equation,  ax^2+bx+c = 0 the value of discriminant determines the nature of roots and is equal to:

D = b^2-4ac

If D>0 then roots are distinct and real.

If D<0 then no real roots.

If D= 0 then there exists two equal real roots.

Given the quadratic equation,  2x^2 - 3x +5 = 0.

Comparing with general to get the values of a,b,c.

a = 2, b =-3,\ c= 5

Finding the discriminant:

D= (-3)^2 - 4(2)(5) = 9-40 = -31

\because D<0

Here D is negative hence there are no real roots possible for the given equation.


Posted by

Divya Prakash Singh

View full answer