Q1 Find the principal and general solutions of the following equations:

\tan x= \sqrt{3}

 

 

Answers (1)

It is given that given 
\tan x= \sqrt{3}
Now, we know  that \tan\frac{\pi}{3}= \sqrt3 and \tan\frac{4\pi}{3}= \tan \left ( \pi+\frac{\pi}{3} \right )=\sqrt3

Therefore,
the principal solutions of the equation are x = \frac{\pi}{3},\frac{4\pi}{3}
Now,
The general solution is \tan x =\tan \frac{\pi}{3}

x =n{\pi} + \frac{\pi}{3}  where n \ \epsilon \ Z and Z denotes sets of integer

Therefore,  the general solution of the equation is x =n{\pi} + \frac{\pi}{3}  where n \ \epsilon \ Z and Z denotes sets of integer

Most Viewed Questions

Preparation Products

Knockout NEET May 2024

Personalized AI Tutor and Adaptive Time Table, Self Study Material, Unlimited Mock Tests and Personalized Analysis Reports, 24x7 Doubt Chat Support,.

₹ 40000/-
Buy Now
Knockout NEET May 2025

Personalized AI Tutor and Adaptive Time Table, Self Study Material, Unlimited Mock Tests and Personalized Analysis Reports, 24x7 Doubt Chat Support,.

₹ 45000/-
Buy Now
NEET Foundation + Knockout NEET 2024

Personalized AI Tutor and Adaptive Time Table, Self Study Material, Unlimited Mock Tests and Personalized Analysis Reports, 24x7 Doubt Chat Support,.

₹ 54999/- ₹ 42499/-
Buy Now
NEET Foundation + Knockout NEET 2024 (Easy Installment)

Personalized AI Tutor and Adaptive Time Table, Self Study Material, Unlimited Mock Tests and Personalized Analysis Reports, 24x7 Doubt Chat Support,.

₹ 3999/-
Buy Now
NEET Foundation + Knockout NEET 2025 (Easy Installment)

Personalized AI Tutor and Adaptive Time Table, Self Study Material, Unlimited Mock Tests and Personalized Analysis Reports, 24x7 Doubt Chat Support,.

₹ 3999/-
Buy Now
Boost your Preparation for JEE Main with our Foundation Course
 
Exams
Articles
Questions