Find the standard form of

            (i)     \frac{-18}{45}                        (ii)     \frac{-12}{18}

Answers (1)

(i) Given fraction \frac{-18}{45}.

We can make it in the standard form :

\frac{-18}{45} = \frac{-6\times3}{15\times3} = \frac{-2\times3\times3}{5\times3\times3} = \frac{-2}{5}

(i) Given fraction \frac{-12}{18}.

We can make it in the standard form :

\frac{-12}{18} = \frac{-6\times2}{9\times2} = \frac{-2\times3\times2}{3\times3\times2} = \frac{-2}{3}

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