Find the standard form of            (i)     $\frac{-18}{45}$                        (ii)     $\frac{-12}{18}$

D Divya Prakash Singh

(i) Given fraction $\frac{-18}{45}$.

We can make it in the standard form :

$\frac{-18}{45} = \frac{-6\times3}{15\times3} = \frac{-2\times3\times3}{5\times3\times3} = \frac{-2}{5}$

(i) Given fraction $\frac{-12}{18}$.

We can make it in the standard form :

$\frac{-12}{18} = \frac{-6\times2}{9\times2} = \frac{-2\times3\times2}{3\times3\times2} = \frac{-2}{3}$

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