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Find the standard form of

(i) $\frac{-18}{45}$ (ii) $\frac{-12}{18}$

Answers (1)

D Divya Prakash Singh

(i) Given fraction $\frac{-18}{45}$ .

We can make it in the standard form :

$\frac{-18}{45} = \frac{-6\times3}{15\times3} = \frac{-2\times3\times3}{5\times3\times3} = \frac{-2}{5}$

(i) Given fraction $\frac{-12}{18}$ .

We can make it in the standard form :

$\frac{-12}{18} = \frac{-6\times2}{9\times2} = \frac{-2\times3\times2}{3\times3\times2} = \frac{-2}{3}$

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