# Q : 9     Find the value of $\small p$ so that the three lines  $\small 3x+y-2=0,px+2y-3=0$  and   $\small 2x-y-3=0$  may intersect at one point.

Point of intersection of lines $\small 3x+y-2=0$ and $\small 2x-y-3=0$ is  $(1,-1)$
Now, $(1,-1)$ must satisfy equation $px+2y-3=0$
$p(1)+2(-1)-3=0$
$p-2-3=0$
$p=5$
Therefore, the value of p is $5$