# Q.11     Given two independent events A and B such that $P(A)=0.3,P(B)0.6,$  Find               (iii) $P(A\; or \; B)$

$\inline P(A)=0.3,P(B)=0.6,$

$P(A\cap B)=0.18$

$P(A\; or \; B)=P(A\cup B)$

$P(A\cup B)=P(A)+P(B)-P(A\cap B)$

$=0.3+0.6-0.18$

$=0.9-0.18$

$=0.72$

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