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Q.11   Given two independent events A  and B  such that P(A)=0.3,P(B)=0.6,  Find 

                (iv)  P(neither\; A\; nor\; B)

Answers (1)



P(A\cap B)=0.18

P(A\; or \; B)=P(A\cup B)

P(A\cup B)=P(A)+P(B)-P(A\cap B)




P(neither\; A\; nor\; B) =P(A'\cap B')

                                         = P((A\cup B)')

                                        =1-P(A\cup B)



Posted by

seema garhwal

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