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Q.11 Given two independent events $A$ and $B$ such that $P(A)=0.3,P(B)=0.6,$ Find

(iv) $P(neither\; A\; nor\; B)$

Answers (1)

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$P(A)=0.3,P(B)=0.6,$

$P(A\cap B)=0.18$

$P(A\; or \; B)=P(A\cup B)$

$P(A\cup B)=P(A)+P(B)-P(A\cap B)$

$=0.3+0.6-0.18$

$=0.9-0.18$

$=0.72$

$P(neither\; A\; nor\; B)$ $=P(A'\cap B')$

$= P((A\cup B)')$

$=1-P(A\cup B)$

$=1-0.72$

$=0.28$

Posted by

seema garhwal

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