3.12 How much charge is required for the following reductions:

           (iii)MnO_{4}^{-}\ to\ Mn^{2+}\ ?

Answers (1)

The given reaction can be written as:- 

                                         Mn^{+7}\ +\ 5e^- =\ Mn^{+2}

Thus charge required in above equation =\ 5F

                                                                = 5(96500)

                                                                = 482500\ C

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