3.13    How much electricity in terms of Faraday is required to produce

              (ii)40.0 g of AI from molten AI_{2}O_{3} ?

Answers (1)

The equation for the given question is :- 

                                       Al^{+3}\ + 3e^-\ =\ Al

Thus for 1 mol of Al, charge required is 3F.

So the required amount of electricity in terms of charge will be :- 

                                                                           =\ \frac{3}{27}\times40F = 4.44F

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