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If \cos^{-1}x> \sin^{-1}x , then 

A. \frac{1}{\sqrt{2}}< x\leq 1

B. 0\leq x< \frac{1}{\sqrt{2}}

C.-1\leq x< \frac{1}{\sqrt{2}}


Answers (1)

Answer :(C)

Plotting cos-1 x and sin-1 x, we get,

As, graph of cos-1 x is above graph of sin-1 x in \left [ -1,\frac{1}{\sqrt{2}} \right ).

So, cos–1x > sin–1 x for all x in \left [ -1,\frac{1}{\sqrt{2}} \right ) .

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