1.25 If NaCl is doped with 10–3 mol % of SrCl2, what is the concentration of cation vacancies?
NaCl is doped with 10–3 mol % of
Concentration in % so that take a total of 100 mol of solution.
Moles of NaCl = 100 - moles of
Moles of is very less , so we can neglect them.
Moles of NaCl =100
1 mole of NaCl is dipped with = mol of .
So cation vacanties per mole of NaCl = mol
So cation vacancies per mol of NaCl =
Hence, the concentration of cation vacancies.
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