2.26   If the density of some lake water is 1.25g\; mL^{-1} and contains 92\; g of Na^{+}\; ions per kg of water, calculate the molality of Na^{+}\; ions in the lake.

Answers (1)

We know that, Molality :

                                          Molality = \frac{Moles\ of\ solute}{Mass\ of\ solvent\ in\ Kg}

So, for moles of solute we have :   

                           Moles\ of\ Na^+ = \frac{92}{23} = 4

Thus,  molality :  

                                      = \frac{4}{1} = 4

Molality of Na+ ions is 4m.

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